Question

The value of cosec 610° + root 3 sec 650° is​

Answer 1

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Answer:

cosec 610° + √3 sec 650°

=1/ sin 610° + √3/ cos 650°

=cos 610° + √3 sin 650°

= 2{ cos 610° + √3 sin 650° / 2sin 10° cos10°{

[multiplying and dividing by 2]

2{cos 610° + √3 sin 650° / sin 20°}

[ Again multiply and divide by 2]

=4[sin30°cos10°−cos30°sin10°/ sin20°]

=4[ sin(30°−10°)/ sin20°]

[∴sin(A−B)=sinAcosB−cosAsinB]

=4[sin20°/sin20°]

=4

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