Math, asked by peducation52, 10 months ago

The value of (cosec A- sin A) (sec A - Cos A) (tan A +cot A)​

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Answered by sandy1816
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Answer:

(coseca - sina)(sec - cosa)(tana + cota) \\  = (1 - sin {}^{2} a \div sina)(1 - cos {}^{2} a \div cosa)(sin {}^{2} a + cos {}^{2} a ÷ sinacosa) \\  = (cos {}^{2} a  \div sina)(sin {}^{2} a \div cosa)(1 \div sinacosa) \\  = (sin {}^{2} acos {}^{2} a \div sinacosa)( 1 \div sinacosa) \\  = sinacosa \div sinacosa \\  = 1

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Answered by Anonymous
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