Question

the value of cosø.tanø​

Answer 1

$\huge\bf{\orange{\underline{\underline{\mathcal{AnSwer}}}}}$

:$\implies$ $\sf CosØ.TanØ$

:$\implies$ $\sf CosØ.\dfrac{SinØ}{CosØ}$

:$\implies$ $\sf SinØ$

$\small\bf\orange{@Jiya871}$

Answer 2

Ratios Used:-

$\underline\pink{\boxed{\bf TanØ = \dfrac{SinØ}{CosØ}}}$

Solution:-

$\dashrightarrow$ $\sf CosØ×\dfrac{SinØ}{CosØ}$

$\dashrightarrow$ $\sf SinØ$