The value of cot lº + cot2 + cot3° + cot4 +............ + cot179 is equal to
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Step-by-step explanation:
cot1°+ cot2°+cot3°+cot4°+..............+ cot179°
means
cot(1+2+3+4+.......179)
first solve underlined part
it is in A.P
therfore
using formula of sum of n th term
Sn = n [t1 +tn]
2
Sn= n [1+179]
2
Sn = 179 * 180
2
Sn = 179 * 90
Sn = 16,110
therefore
cot(16110)
=0
hope helps you
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