Question

The value of cot54°/tan36° + tan20°/cot70° is

(a) 2
(b) 3
(c) 1
(d) 0

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Answer 1

Step-by-step explanation:

=Cot54/tan36 + tan20/cot70 -2tan45

=As we know that cot (90-x)=tan x

=cot(90-36)/tan36 + tan(90-70)/cot70 - 2

=tan36/tan36 + cot70/cot70 - 2

=1+1-2

= 0

Answer 2

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This is the best possible answer

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