Question

the value of critical volume Vc according to vanderwalls equation is​

Answer 1

Answer:

P=RTV−b−aV2. 2TR(V−b)3−6aV4=0. Eliminate RT/a from these to find the critical molar volume of a van der Waals gas: Vc=3b.

Answer 2

The value of critical volume Vc according to vanderwalls equation is​ 3b.

(P+a/V^2)+(V−b)=RT

Rearrange the above in terms of P

we know dp/dv=0 ---1

we also know dp^2/dv^2=0----2

find out 1 and 2 and divide and equate 2/1