The value of currenti in the following circuit is
Answers
Answer:
According to Kirchhoff's first law, total entering current into the circuit = total leaving current from the circuit. i.e, 10+1+2=i or i=13A
Explanation:
First step, note that there is a short circuit in parallel with 5 and 7 ohm resistors. The resistance of that combination is zero.
Once you have done that, note that the 3.5 and 3 ohm resistors are in series, so their total resistance is 6.5 ohms.
The 6.5 ohms are in parallel with the 4 and 2 ohm resistors. To find their effective resistance, lets call it Ra, use the formula for parallel resistors
Now you are left with a much simpler circuit to analyze, a 25 volt battery, a 1 ohm resistor, and Ra in series.
The current flowing in that circuit will be from Ohm’s law (I=V/R) simply
I =25/(Ra+1)
That will be the current flowing in the 1 ohm resistor.
The voltage drop across the parallel combination of resistors will, again from ohms law (V=IR), as follows
Now the current flowing through the 2 and 4 ohm resists can be calculated using ohms law I = Va/Rx.
The current through the 3.5 and 3 ohm resistor will be the current calculated from I =Va/(3.5+3)
There will be zero voltage drop across the 5 and 7 ohm resistors due to the short, so no current will flow in them.