Question

The value of d/dt( sinx) ,where x and t are the variables
options
1.may be zero
2. may be non zero
3. must be negative
4. must be positive

This question has multiple answers
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Answer 1

Answer:

As per the question says, we have

=> d(sinx)/dx

=> cosx

and we know cosx takes values between -1 to 1.

So it can take values that maybe be zero, non-zero, negative and non-negative.

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Answer 2

Answer:

the answer above is wrong because they asked differentiation of sinx with respect to dt which isn't possible so it can be zero or non zero

Explanation:

mentioned above