Question

The value of d/dx(sin2x+cos2x) is

Answer 1

$</p><p> \sf \rightarrow \quad \frac{dy}{dx} = \frac{d}{dx} \left( sin \: 2x + cos \: 2x \right) \\ \\ \sf \rightarrow \quad \frac{dy}{dx} = \frac{d(sin \: 2x)}{dx} + \frac{d(cos \: 2x}{dx} \\ \\ \sf \rightarrow \quad \frac{dy}{dx} = \bigg\{ \frac{d(sin \: 2x)}{d \: 2x} \: \cdot \: \frac{d(2x)}{dx} \bigg\} + \bigg\{ \frac{d(cos \: 2x)}{d \: 2x} \: \cdot \: \frac{d(2x)}{dx} \bigg\} \\ \\ \sf \rightarrow \quad \frac{dy}{dx} = (cos \: 2x \: \cdot \: 2 ) + ( - sin \: 2x \: \cdot \: 2) \\ \\ \sf \rightarrow \quad \frac{dy}{dx} = 2(cos \: 2x - sin \: 2x)</p><p></p><p>$