Question

the value of delta e when the system absorbs 1000 kilo joule of heat and does 650 kilo joule of work on the surroundings is​

Answer 1

Answer:

The correct answer is 1650 kJ

Answer 2

Answer:

The value of ΔE, i.e., change in internal energy measured is $350kJ$.

Explanation:

Given,

The heat absorbed by the system, Q = $1000kJ$

Heat absorbed by the system is taken as positive.

The work done by the system, W = $650kJ$

Work done by the system is taken as negative.

Therefore,

The work done by the system, W = $-650kJ$

The value of ΔE, i.e., the change in internal energy =?

As we know,

• ΔE =$Q +W$

After putting the given values in the equation, we get:

• ΔE = $1000kJ + ( -650kJ)$
• ΔE = $1000kJ -650kJ$
• ΔE = $350kJ$

Hence, the value of ΔE, i.e., the internal energy change = $350kJ$.