Math, asked by swativinayakbhat1, 5 months ago

The value of derivative of function y=16 xcube at x=-1 is​

Answers

Answered by princeuplucky123449
1

Answer:

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Step-by-step explanation:

y = 16x^3 + 16x^2

dy / dx = 16 * (3x^2) + 16 * (2x) = 48x^2 + 32x

At x = (- 1):

dy / dx = 48 * 1 + 32 * (- 1) = 48 - 32 = 16

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