Question

the value of discriminant of quadratic equation x²-2x+1=0 will be :​

Answer 1

Answer :-

Given :-

• Quadratic equation : x²-2x+1=0

To Find :-

• Value of discriminant

Solution :-

Discriminant = b² - 4ac

where

• a is coefficient of x²
• b is coefficient of x
• c is constant

For the given equation :-

• a = 1
• b = -2
• c = 1

→ D = b² - 4ac

→ D = (-2)² - 4 × 1 × 1

→ D = 4 - 4

→ D = 0

Value of Discriminant = 0

Answer 2

For the equation x²-2x+1=0 :-

• a = 1
• b = -2
• c = 1

$→ \bold \red {D = b² - 4ac} \\ \\ → D = (-2)² - 4 × 1 × 1 \\ \\ → D = 4 - 4 \\ \\ → D = 0$

Value of Discriminant = 0

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