The value of dy/dx at x=90 degree where y = e^sinx
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Step-by-step explanation:
Given ----> y = eˢⁱⁿˣ
To find---> dy / dx at x = π / 2
Solution---> We have some formula of differentiation as follows,
(1) d / dx ( eˣ ) = eˣ
(2) d / dx ( Sinx ) = Cosx
ATQ,
y = eˢⁱⁿˣ
Diffrrentiating with respect to x
=> dy / dx = d / dx ( eˢⁱⁿˣ )
=> dy / dx = e ˢⁱⁿˣ d / dx ( Sinx )
=> dy / dx = eˢⁱⁿˣ ( Cosx )
dy / dx at x = 90°
= eˢⁱⁿ⁹⁰ ( Cos90° )
= e¹ ( 0 )
= 0
Additional information--->
1 ) d / dx ( Cosx ) = - Sinx
2) d / dx ( tanx ) = Sec²x
3) d / dx ( Secx ) = Secx tanx
4) d / dx ( Cosecx ) = - Cosecx Cotx
5) d / dx ( Cotx ) = - Cosec²x
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0(zero)
#answerwithquality #bal
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