Question

the value of electric field at the centre of hollow spherical metalic shell of radius 5m, having positive charge of 10c is. 2NC-1 , 0,10nc-1, 5nc-1​

Answer 1

To find:

The value of electric field at the centre of hollow spherical metalic shell of radius 5m, having positive charge of 10C.

Calculation:

Let surface area be denoted as s , Field Intensity be denoted as E;

Applying Gauss' Theorem:

$\displaystyle \therefore \: \oint \vec{E} \: . \: \vec{ds} = \dfrac{q_{enclosed}}{\epsilon_{0}}$

$\displaystyle = > \: \oint E \times ds \times \cos( \theta) = \dfrac{q_{ enclosed}}{\epsilon_{0}}$

$\displaystyle = > \: E \oint ds \times \cos( \theta) = \dfrac{q_{ enclosed}}{\epsilon_{0}}$

Now , in a spherical conductor the whole charge is present along the surface of the conductor. Hence , the net charge enclosed within the conductor will be zero.

$\displaystyle = > \: E \oint ds \times \cos( \theta) = \dfrac{0}{\epsilon_{0}}$

$\displaystyle = > \: E \oint ds \times \cos( \theta) = 0$

$\displaystyle = > \: E = 0$

So, final answer is:

$\boxed{ \bf{ \: E = 0}}$