Question

The value of electric field inside a conducting sphere having radius R and charge Q will a) KQ/R^2 b) KQ/R c) Zero d) KQ^2/R^2

Answer 1

Answer:

Zero

Explanation:

Because the charge on a conducting sphere will be on its surface only , so if there is no charge inside the conducting sphere , there will be no electric field

Answer 2

The value of electric field inside a conducting sphere having radius R and charge Q will be

(a) KQ/R²

(b) KQ/R

(c) zero

(d) KQ²/R²

answer : option (c) zero.

According to Guass’ theorem, “electric flux through the Gaussian surface is proportional to the net charge enclosed in it.” as electric field is directly depends on the electric flux. so the electric field also proportional to the net charge enclosed in the surface.

but here, if we put some charge on the conducting sphere, all charges lies on the outside of conducting surface. This is because Gauss’ law , it says that electric flux through the closed surface must be zero.

since, net charge inside the conducting sphere is zero, it is obvious that the electric field inside the conducting sphere will be zero.

in short, The value of electric field inside a conducting sphere will be zero because all charge lies on the outside of sphere.

Therefore the correct option is (c) zero.