Question

The value of electric field intensity is to be

given an α-particle so that its acceleration is

equal to the acceleration due to gravity ‘g’ is

(where ‘m’ is the mass of proton and ‘e’ is

charge of proton).
​

Answer 1

Explanation:

$\sf \alpha \: Particle : {}_{2}{He}^{4} \\ \\ \sf So\:mass\:of\: \alpha \: particle (M) = 4m \\ \\ \sf Charge\:on\: alpha\: particle (q) = 2e \\ \\ \sf Acceleration \:of\:alpha\: particle\:(a) = g \:m\:{s}^{-2} \\ \\ \sf Let\:the\:electric\:field\: intensity \: be \: E \\ \\ \sf we\:know\:that \\ \\ \sf F = qE \\ \\ \sf But\: F = Ma \\ \\ \sf \longrightarrow Ma = qE \\ \\ \sf Rearrange \:the\: equation\:for \: E \\ \\ \sf \longrightarrow E = \frac{Ma}{q} \\ \\ \sf Substituting\:the\:know\:values \\ \\ \sf \longrightarrow E = \frac{4mg}{2e} \\ \\ \sf \longrightarrow E = \frac{2mg}{e} \\ \\ \sf This \:is\:the\:required\:value\:electrical\:field\: intensity$

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Answer 2

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