Question

The value of electric potential a electric
field due to given charge are
& 100N/c respectively 300 volt the magnitude
of charge will be​

Answer 1

Explanation:

ANSWER

V=600v=

x

k8

E=200=

x

2

k8

⇒

200

600

=x

⇒x=3

Now,

Q=

9×10

9

600×3

⇒Q=2×10

−7

⇒Q=0.2μC

Hence, answer is Q=.2....c