Question

The value of enthalpy change for the reaction, C2H5OH(l) + 3O2(g) ---> 2CO2(g) + 3H2O(l) at 27 degree celcius is -1366.5 kJ/mol. The value of internal energy change for the reaction at this temperature will be:
a) – 1371.5 kJ
b) - 1369 kJ
c) - 1364 kJ
d) – 1361.5 kJ

Answer 1

Answer:

the temperature will be -1364 kJ

Explanation:

hope it helps

Answer 2

Your answer is in the attachment hope it helps you dear

so your answeris the(c).