Question

The value of enthalpy change ($\Delta H$) for the reaction $C_2H_5OH(l) + 3O_2(g) \rightarrow 2CO_2(g) + 3H_2O(l)$ at 27° C is – 1366.5 kJ mol⁻¹. The value of internal energy change for the above reaction at this temperature will be :
(a) – 1369.0 kJ
(b) – 1364.0 kJ
(c) – 1361.5 kJ
(d) – 1371.5 kJ

Answer 1

B

delta H= change in internal energy + ( no of gaseous product molecules - no of gaseous reactant molecules)* RT