Question

The value of f(√3) when f(x) = 3x³ + 10 is

Answer 1

Answer:

Factor Theorem :

Let p(x) be a polynomial of

degree one or more than 1

and a is a real number . Then

i ) x - q , will be a factor of p(x)

if p(a) = 0 conversely

ii ) If x - a is a factor of p(x) ,

then p(a) = 0

****************************************

Here,

F(x) = 3x³ + x² -20x + 12,

g(x) = 3x - 2 ,

g(x) = 0

=> 3x - 2 = 0

=> x = 2/3

Zero of g(x) = 2/3 ,

Now ,

F(2/3) = 3(2/3)³+(2/3)²-20(2/3)+12

= 3(8/27) + 4/9 - 40/3 + 12

= 8/9+4/9-40/3+12

= 12/9 - 40/3 + 12

= 4/3-40/3 + 12

= -36/3 + 12

= -12 + 12

= 0

Answer 2

f(√3) when f(x) = 3x³ + 10

substituting $\sqrt{3}$ in f(x) ==>

we get, =

$3(\sqrt{3}) ^{3} + 10$

$3 * 3\sqrt{3} + 10$

$9\sqrt{3} + 10$

9 * 1.732 + 10

15.588 + 10

25.588 is your answer! hope this helps with your homework.

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