Question

The value of ΔfH⊖ for NH3 is – 91.8 kJ mol–1. Calculate enthalpy change for the following reaction :
2NH3(g) → N2(g) + 3H2(g)
________________________

idhar koi pin use krta hai??
(asking from my followings)​

Answer 1

Answer:

183.6KJ

Explanation:

ΔH for formation is given. For the reverse reaction,ΔHchanges sign as the reverse of exothermic reaction will be endothermic. So, ΔH for decomposition is - (-91.8)=91.8 for one mole. But here, two moles are decomposing,

ΔH=2∗91.8=183.6KJ