Question

The value of first positive term of the AP –13, –9, –5, .... is .....

Answer 1

Step-by-step explanation:

a=−9, d=(−8.25−(−9))=

4

+3

=0.75.

Let T

n

is positive

⇒T

n

=−9+(n−1)0.75

T

n

>0

⇒−9+(n−1).75>0

.75n−.75>9

.75n>9.75

n>

.75

9.75

n>13

Hence 13th term is 0−

14th term is positive −

Hence, the answer is 14.