Question

The value of for which the terms 7K +3,4K-5,2K + 10 are in A.P., is
(a) -13
(6) 23 (c) 13
(d) 23​

Answer 1

Answer:

-23

Step-by-step explanation:

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Answer 2

The value of K = -23

Given:

The terms 7K +3, 4K-5, 2K + 10 are in AP

To find:

The value of K

Solution:

Given 7K +3, 4K-5, 2K + 10 are in AP

here,

First term a₁ = 7K+3  

Second term a₂ = 4K-5

Third term a₃ = 2k+10  

As we know in a AP

Common difference d = 2nd term - 1st term = 3rd term - 2nd term

⇒ 4K- 5 - 7K - 3 = 2K+10 - 4K+ 5  

⇒ -3K - 8 = -2K +15

⇒  3K - 2K = -15 - 8

⇒  K = -23  

The value of K = -23

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