Question

The value of frictional force on block in the given diagram is (Takeg 10 m/s?) [NCERT Pg. 101]

m 3 kg

L(2) 5 N

(4) 9 N

5N

u= 0.3

(1) 4 N

(3) 6 N​

Answer 1

Answer:

2) 5N

Explanation:

See the force = 5N, mu = 0.3 and mass is 3kg

N= mg here.

FS= usB = 0.3x30= 9.0.

Which is greater than the force.

But as we know static friction is self adjustable, the friction would limit itself to 5N only as it only needs to resist a force of 5N

hope it help u

Answer 2

Answer:

thanks...

i hope it's helpful to you...