The value of ‘g’ on Earth is 9.81 m.s^-2. On Mars it is 1/3 that on Earth. An
object is dropped from a height of 6.54 m above the surface of Mars. Then (i) Find the velocity with which it hits the ground of Mars. (ii) If the same object is thrown vertically upward from Earth surface with the velocity with which it hits the surface of Mars, find the greatest height attained by the object.
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answer (i) 6.53m/s
answer (ii) 6.44m
Explanation:
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Answered by
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Answer:
below
Explanation: The value of ‘g’ on Earth is 9.81 m.s-2 . On Mars it is 1/3 that on Earth.
G on Mars=1/3*9.81=3.27m/s^2
i)H=6.54m
V^2=u^2+2gh
V^2=0^2=2(3.27)(6.54)
V^2=42.77
V=6.53 approx.
ii) V^2=u^2+2gh
6.53^2=0^2+2*9.8*h
42.64=0+19.6h
H=2.17m
(these are values upto 2 decimal places for calculation)..
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