Physics, asked by Username12102006, 3 months ago

The value of ‘g’ on Earth is 9.81 m.s^-2. On Mars it is 1/3 that on Earth. An
object is dropped from a height of 6.54 m above the surface of Mars. Then (i) Find the velocity with which it hits the ground of Mars. (ii) If the same object is thrown vertically upward from Earth surface with the velocity with which it hits the surface of Mars, find the greatest height attained by the object.

Answers

Answered by manoj6362l
1

answer (i) 6.53m/s

answer (ii) 6.44m

Explanation:

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Answered by pranabde34
1

Answer:

below

Explanation: The value of ‘g’ on Earth is 9.81 m.s-2 . On Mars it is 1/3 that on Earth.

G on Mars=1/3*9.81=3.27m/s^2

i)H=6.54m

V^2=u^2+2gh

V^2=0^2=2(3.27)(6.54)

V^2=42.77

V=6.53 approx.

ii) V^2=u^2+2gh

6.53^2=0^2+2*9.8*h

42.64=0+19.6h

H=2.17m

(these are values upto 2 decimal places for calculation)..

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