Question

The value of ‘g’ on the earth’s surface is 9.8m/s2

. Suppose the earth suddenly
shrinks to one-third of its present size without losing any mass. What is the value
of ‘g’ on the surface of the shrunken earth?

Answer 1

Answer:

I hope it us help full

Explanation:

Acceleration of gravitation, a=

R

2

GM

Where,

M is mass of earth and R is separation between both masses.

If volume is reduce, keeping mass and separation between them same then.

From the formula it is clear that acceleration of gravity will remain constant.

Hence, value of gwill be 9.8ms

−2

Answer 2

Answer:

it should be 9×(9.8)m/s²

as g=GM/R²(on normal radius of earth )

when earth will shrink then

R'=R/3 resulting g'=9(GM/R²)

and

as g=GM/R² on normal radius

u can replace the value of GM/R² in g' giving u g'=9g.