Question

The value of g on the moon whose diameter is 1/4 that of earth is 1/6 of that of earth . The ratio of escape velocities at moon and earth 's surface is nearly ?

Answer 1

1:3 .............................

Answer 2

Ve² = 2g(e)×R(e)
Vm² = 2g(m)×R(m)
Divide both equ.
Given ratio of g=1/6
ratio of R or D= 1/4
Vm = Ve/√24