Question

The value of g on the surface of earth is 9.8m/s (1) 2 What is its value in a planet of half the mass and with same radius.

Answer 1

Answer:

4.9 m/s²

Explanation:

As $g_{e}$ =  $\frac{GM}{R^{2}}$,

⇒ gₓ = $\frac{G(M/2)}{R^{2}}$

⇒ gₓ = $\frac{1}{2}\frac{GM}{R^{2}}$

⇒ gₓ = $\frac{1}{2}$ · $g_{e}$

∴ Acceleration due to gravity (g) on the unknown planet = 9.8/2

∴ g = 4.9 m/s²

Thanks !