Question

The value of g on the surface of earth is 9.8m/s (1) 2 What is its value in a planet of half the mass and with same radius.

Answer 1

Answer:

4.9m/s

Explanation:

Case 1

Mass =m

Radius =r

g=(Gm)/(r)^2

=9.8m/s

Case 2

Mass=m/2

Radius=r

g*=(Gm)/2(r)^2

=g/2 =9.8/2 = 4.9m/s