The value of g will become 10% of its value at the
earth’s surface at a height ? above the surface of
earth. Take radius of earth as 6400 km. Ans : 57,600
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Answer:
Let g = acceleration due to gravity at the earth surface.
→gh = acceleration due to gravity at the height (h) = 0.64g.
Now,
0.64g = g R²E/(RE + h)²
=> 0.64 (RE + h)² = R²E
=> 0.8h = 0.2 × RE = 0.2 × 6400
=> h= 2 × 6400/8 = 57,600
Explanation:
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