Question

The value of (i19+(1/i)^25)^2 is

Answer 1

Answer:

-4

Step-by-step explanation:

(i19+(1/i)25)2 = (i16 i3+1/i24 i)2

(since i4 = 1, i2 = -1)

= ( -i+1/ i)2

= (-i+i3)2

= (-i-i)2

= (-2i)2

= 4 (-1)

= -4