Question

The value of i⁹⁵ is ---​

Answer 1

Answer:

answer 1

i hope is answer

Answer 2

Solution.

Note that $i^{95}=i^{4\cdot 23+3}=i^{3}=\boxed{-i}$.

Because $i^n$ cycles every 4th number in the exponent.

See this, $i^{1}=i\rightarrow i^{2}=-1\rightarrow i^{3}=-i\rightarrow i^{4}=1\rightarrow...$.

We can say $i^{4n+1}=i, i^{4n+2}=-1, i^{4n+3}=-i, i^{4n}=1$, as it cycles every 4th exponent.