Question

The value of IT1-T2l, in the given diagram, is​

Answer 1

Explanation:

For equilibrium

T2 SIN 60⁰ = 10 X 10

T1 SIN 30⁰ = 5 X 10

T2 COS60⁰ = T1 COS30⁰

T2/T1 = √3 /2 X 2

T2/T1 = √3-------1

|T1-T2| = T2 /√3 - T2

= T2 ( 1/√3 - 1)

= 200/√3 ( 1/√3 - 1)

= 200/3( 1 - √3)

= 200/3( √3 - 1)

modulus of it is positive.