The value of K [ (1 + ∆T/T)^ 4 - 1 ] according to binomial theorem
Answers
Answered by
150
Answer:
Explanation:
=> According to binomial theorem,
(1+x)ⁿ = 1 + nx + (n)(n-1)x² / 2! + ........
=> Here, higher powers are neglected due to very small x.
∴ (1 + x)ⁿ = 1 + nx
k [(1 + ΔT / T₀)⁴ - 1] = k [1 + 4 (ΔT/T₀) - 1]
= 4kΔT/T₀
Thus, the value of K [ (1 + ∆T/T)^ 4 - 1 ] according to binomial theorem is 4kΔT/T₀.
Answered by
53
Answer:According to binomial theorem,
(1+x)ⁿ = 1 + nx + (n)(n-1)x² / 2! + ........
=> Here, higher powers are neglected due to very small x.
∴ (1 + x)ⁿ = 1 + nx
k [(1 + ΔT / T₀)⁴ - 1] = k [1 + 4 (ΔT/T₀) - 1]
= 4kΔT/T₀
Thus, the value of K [ (1 + ∆T/T)^ 4 - 1 ] according to binomial theorem is 4kΔT/T₀.
Explanation:
Similar questions