Question

The value of k for which (25x²+ky) = (5x+4y)(5x-4y)

Answer 1

Answer:

$(25x {}^{2} + ky) = 25x {}^{2} - 20xy + 20xy - 16y {}^{2}$

$25x {}^{2} + ky - 25x {}^{2} + 20xy - 20xy + 16y {}^{2} = 0$

$ky + 16y {}^{2} = 0$

$ky = - 16y {}^{2}$

$k \: = - 16y$

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Answer 2

Answer:

25x^2 + ky= 25 x^2 - 16 y^2

ky=-16 y^2

k=-16y