Question

The value of k for which (–4) is a zero of the polynomial x2 – x – (2k +2) is

(a) 3 (b) 9 (c) 6 (d) –1

Answer 1

Step-by-step explanation:

Here given that -4 is a zero of the polynomial it means that -4 is a solution of this equation so find the value of k by putting -4 on the place of x and also remember one thing at the time of solving these type of questions that is sign because it goes reversed after changing the side it may be from left to right or vice versa

solution:

x^2-x-(2k+2)=0

(-4^2)-(-4)-2k -2=0

16+4-2k-2=0

2k=18

k=9

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Answer 2

$\huge\purple {\boxed {\mathfrak {☆AnSwEr☆☆}}}$

$\sf\green{\underline {\sf Let ,}}$

$p(x) = {x}^{2} - x - (2k + 2)$

$\sf\red {\underline {\sf If ,}}$

-4 is a zero of p (x) ,then

$p(x) = 0$

${( - 4)}^{2} - ( - 4) - (2k +2 ) = 0$

$16 + 4 - 2k - 2 = 0$

$20 - 2k - 2 = 0$

$18 - 2k = 0$

$2k = 18$

$k = \frac{18}{2}$

$k = 9$

$\huge\mathcal {Hope\:It\:Helps\:You}$