Question

the value of k for which kx^2-4x+4=0 has real equation and equal root​

Answer 1

☆SoluTion =》

Answer:-

k=1

Given =》

▪︎ kx²-4x+4=0

To find=》

value of k

Explanation =》

kx²-4x+4=0

On comparing to the general form ax² +bx+c=0

a= k , b= -4 , c= 4

for real and equal roots

D=0 ( D= b²-4ac)

b²-4ac=0

(-4)²- 4× k×4=0

16- 16k=0

-16k=-16

k= -16/16

k=1

value of k is 1

Answer 2

$\rule{200}3$

$\Huge{\red{\underline{\textsf{Answer}}}}$

$\green\bigstar$It is given that the equation has equal and real roots.

$\therefore$ $\sf The \ discriminant \ of \ the \ equation = 0.$

$\orange\longrightarrow$ $\orange{\sf b^{2} - 4ac}$

$\purple\star$ $\purple{\sf a = k, \: b = -4, \: c = 4}$

$\red\longrightarrow$ $\red{\sf -4^{2} - 4 \times k \times4}$

$\red\longrightarrow$ $\red{\sf 16 - 16k = 0}$

$\red\longrightarrow$ $\red{\sf -16k = -16}$

$\blue\longrightarrow$ $\huge{\boxed{\blue{\sf k = 1}}}$

$\rule{200}3$

❤️$\mathcal{BE \: BRAINLY}$❤️

$\rule{200}3$