The value of k for which kx2 + 5x + 1 =
0, has equal roots is
Answers
Answered by
3
hi mate your answer↓
the roots are real and equal
a=k, b= 5,c=1
b^2-4ac=0
5^2-4×k×1=0
25-4k=0
-4k=-25
k=25/4
hope that it will help you
the roots are real and equal
a=k, b= 5,c=1
b^2-4ac=0
5^2-4×k×1=0
25-4k=0
-4k=-25
k=25/4
hope that it will help you
gourimisale11:
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Answered by
3
The given equation is
Kx^2 +5x +1 =0
Comparing the given equation with
ax^2 +bx +c = 0
We get
a =k, b =5, c =1
We have
b^2 - 4ac = 5^2 - 4 *k *1
=25 - 4k
Given
b^2 - 4ac =0
Hence
25 - 4k =0
25 =4k
25 /4 =k
K =25 /4
I HOPE YOU CAN UNDERSTAND IT
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Kx^2 +5x +1 =0
Comparing the given equation with
ax^2 +bx +c = 0
We get
a =k, b =5, c =1
We have
b^2 - 4ac = 5^2 - 4 *k *1
=25 - 4k
Given
b^2 - 4ac =0
Hence
25 - 4k =0
25 =4k
25 /4 =k
K =25 /4
I HOPE YOU CAN UNDERSTAND IT
MARK ME AS A BRAINLIST
Say thanks to me by click on thanks button
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