Math, asked by juvia647, 9 months ago

The value of k, for which one root of the quadratic equation kx2 -14x +8 =0 is six times the other.

Answers

Answered by PrithwiCC
0

Answer:

Let a root be r. Then other root is 6r

Then, r+6r = - (-14)/k and r.6r = 8/k

Hence, 7r = 14/k i.e r = 2/k

So, 6.(2/k)^2 = 8/k

=> 24/(k^2) = 8/k

=> k = 3

Step-by-step explanation:

Putting k you get the roots as 4 and 2/3 which are the roots of the equation. Also, 4 is 6 times that of 2/3

Answered by srijansarvshresth135
0

Answer:

k=3

Step-by-step explanation:

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