Question

The value of k for which pair of linear equations 3x + k y = 10 and k x + 12 y = 5 have infinitely many solutions (A) – 6 (B) 6 (C) ± 6 (D) None​

Answer 1

Step-by-step explanation:

Given 

kx+3y−(k−3)=0

Comparing with a1x+b1y+c1=0

∴a1=k, b1=3, c=−(k−3)

12x+ky−k=0

Comparing with a1x+b1y+c1=0

∴a1=12, b1=k, c=−k

Since equation has infinite number of solutions

So, a2a1=b2b1=c2c1

12k=k3=kk−3

12k=

Answer 2

Answer:

3x+ky= 10

kx+12y=5

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4kx+11ky=5

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Step-by-step explanation:

None is the correct answer❤☺