Question

The value of K for which quadratic
kx² + 2kx-(k-1) has equal root
is​

Answer 1

Step-by-step explanation:

kx²+2kc-(k-1)=0

use the formula b2-4ac OK friend this is urs answer

Answer 2

ANSWER:

★ QUADRATIC RESOLUTION ★

Given equation :

kx² - kx + 1 = 0

For equal roots :

D = 0

k² - 4( k ) = 0

k² = 4k

k = 4

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Please mark my answer Brainliest answer.