Math, asked by tanuaes2016, 10 months ago

the value of k for which system of equations x+y-4 = 0 and 2x+ky=3 has no solution, is​

Answers

Answered by dhaval211004
18

Step-by-step explanation:

IF SYSTEM OF EQUATIONS HAS NO SOLUTION THEN

a1/a2=b1/b2=/=c1/c2

hence \: we \: get \:  \frac{1}{2}  =  \frac{1}{k}  \\  \: therefore \\ k = 2

Answered by llsmilingsceretll
3

EXPLANATION.

Roots of the equation.

  • 3x² - 10x + k = 0. are reciprocal to each other.

As we know that,

  • Let one roots be = α.
  • Other roots is reciprocal to each other = 1/α.

Products of the zeroes of the quadratic polynomial.

⇒ αβ = c/a.

⇒ α x 1/α = k/3.

⇒ 1 = k/3.

⇒ k = 3.

                                                                                                                         

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.

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