Question

The value of k for which the equation 2xsquare - kx + k =0 has real roots

Answer 1

Answer:

k = 0 or 8.

Step-by-step explanation:

For the equation for calculating roots in equation of  form ax² + bx + c = 0, for real roots,  the determinant should be greater than or equal to zero i.e. b² - 4ac ≥ 0.

So in equaition 2x² - kx  + k = 0

a = 2, b = - k,  c = k

b² - 4ac ≥ 0

=> k² - 8k ≥ 0

=> k(k-8) ≥ 0

=> k = 0 or 8.

There fore value of k is 0 or 8.