Question

the value of k for which the equation 3x -y +8 =0 k6 +1ky =-16 represent incident lines is​

Answer 1

Step-by-step explanation:

6k+ky=-16

or,6k+ky+16=0

I can write,

3x-y+8=6k+ky+16

or,. 3x-y+8=k(6+y)+16

or,. k(6+y)=3x-y+8-16=3x-y-8

or,. k=3x-y-8/6+y=3x-2y-14