Question

the value of k for which the equation 4x^2+kx=0 has equal and real roots​

Answer 1

For real and equal roots,

D = 0

b²-4ac = 0

(k)² - 4 x 4 x 0 = 0

k² = 0

k = 0

Answer 2

Step-by-step explanation:

given

${4x}^{2} + kx = 0$

if the roots are real and equal then delta =0

delta =

${b}^{2} - 4ac = 0$

a=4 ,b=k ,c=0

k^2 -4(4)(0)=0

k^2=0

k=0

Hope it helps you....