Math, asked by kanuqwerty50, 1 year ago

The value of ‘K’ for which the equation kx^2+12x+9=0 has equal roots is:​

Answers

Answered by akankshappatil16
5

Answer:

Step-by-step explanation:

The function will have imaginary roots when the determinant is negative.  The determinant = (b(squared)-4ac

so: 12(squared) - 4(k)(9)<0

144-36k<0

-36k<-144

k>4

Answered by kushagrasingh5p501ca
1

Answer:

The function will have imaginary roots when the determinant is negative.  The determinant = (b(squared)-4ac

so: 12(squared) - 4(k)(9)<0

144-36k<0

-36k<-144

k>4

Step-by-step explanation:

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