The value of k for which the equation x2-4x+Kequals to 0 has equal roots
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x2-4x+k=0
b2-4ac=0
ie, (-4)^2 -4×1×k=0
16-4k=0
-4k=-16
k=-16/-4=4
b2-4ac=0
ie, (-4)^2 -4×1×k=0
16-4k=0
-4k=-16
k=-16/-4=4
Answered by
3
Therefore the value of k is 4.
Hope it helps!
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