Math, asked by amansinghjatt8164, 1 year ago

The value of k for which the equation x2-4x+Kequals to 0 has equal roots

Answers

Answered by abhishekellath

2

x2-4x+k=0
b2-4ac=0
ie, (-4)^2 -4×1×k=0
16-4k=0
-4k=-16
k=-16/-4=4

Answered by QueenOfKnowledge

3

Therefore the value of k is 4.

Hope it helps!

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