Question

the value of k for which the following pair of equations has no solution (3 k + 1) X + 11 Y - 22 is equals to zero X +( 2 k - 1) Y - 4 is equal to zero is​

Answer 1

Answer:

Given : (3k+1)x + 3y - 2 = 0 ; (k2+1)x+(k−2)y−5=0(k2+1)x+(k−2)y−5=0

For a system which has no solution,

a1a2=b1b2≠c1c2a1a2=b1b2≠c1c2

∴3k+1k2+1=3k−2≠25∴3k+1k2+1=3k−2≠25

⟹3k+1k2+1(3k+1)(k−2)⟹3k2−6k+k−2−5k∴k=3k−2=3(k2+1)=3k2+3=5=−1