the value of k for which the line representing the equation 2x-y=5 y=kx+5
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Here, kx – 5y + 4 = 0
⇒ y = kx + 4/5
∴ The slope of the line is k/5.
Also 4x – 2y + 5 = 0
Y = 2x + 5/2
∴ The slope of line is 2.
Since the given lines are perpendicular to each other, we have
(k/5)(2) = - 1 ⇒ k = - 5/2
⇒ y = kx + 4/5
∴ The slope of the line is k/5.
Also 4x – 2y + 5 = 0
Y = 2x + 5/2
∴ The slope of line is 2.
Since the given lines are perpendicular to each other, we have
(k/5)(2) = - 1 ⇒ k = - 5/2
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