Question

The value of K for which the lines ( K + 1 )x + 3Ky +15 = 0 and 5x + Ky + 5 = 0 are

coincident in :​

Answer 1

Answer:

k=14

Step-by-step explanation:

The given equations are:

(k+1)x+3ky+15=0, and

5x+ky+5=0

Since, the given equations are coincident, therefore

\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}

\frac{k+1}{5}=\frac{3k}{k}=\frac{15}{5}

Taking the first two terms, we have

k=14

Answer 2

Answer:

HEY

Step-by-step explanation:

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